A dynamite blast at a quarry launches a rock straight upward and 1.5s later it is rising at a rate of 11m/s. Assuming air resistance has no effect on the rock calculate its speed (a) at launch and (b) 5.1s after launch. I have gotten the answer for (a) which is 25.7m/s however I can not get (b). I have tried using the V=vo+at formula to get (b) which gives you -24.28 but this answer keeps on coming up as incorrect. I’m unsure what to do next.
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