The movement of the ball is evenly accelerated.
We can write
2as=v2−v02(1)2as=v^2-{v_0}^2 (1)2as=v2−v02(1)
In our case, v0=0m/s, v=485 m/s, s=0.8 m
Using (1) we get
a=v22s(2)a=\frac{ v^2}{2s} (2)a=2sv2(2)
We have
a=147015 m/s2
The acceleration is given by formula
a=v−v0t(3)a=\frac{v-v_0}{t} (3)a=tv−v0(3)
Using (3) we get
t=v−v0a(4)t=\frac{v-v_0}{a} (4)t=av−v0(4)
Answer
a) 0.0033 s
b) 147015 m/s2
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