Answer to Question #96345 in Mechanics | Relativity for Alaa

Question #96345
A rifle is found to give the bullet a muzzle velocity of 485 m/s the barrel is 80cm long
a) how much time is the bullet moving in the barrel?
b) what is the average acceleration of the bullet?
1
Expert's answer
2019-10-14T09:13:10-0400

The movement of the ball is evenly accelerated.

We can write


2as=v2v02(1)2as=v^2-{v_0}^2 (1)


In our case, v0=0m/s, v=485 m/s, s=0.8 m

Using (1) we get

a=v22s(2)a=\frac{ v^2}{2s} (2)


We have

a=147015 m/s2


The acceleration is given by formula

a=vv0t(3)a=\frac{v-v_0}{t} (3)


Using (3) we get

t=vv0a(4)t=\frac{v-v_0}{a} (4)


Answer

a)     0.0033 s

b)     147015 m/s2

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