Question #96242

A body of mass 20kg was projected into space at an angle of 40° calculate
(a)time taken to reach the maximum height
(b)the maximum height reached
(c)the range

Expert's answer

When body is launched with initial velocity v0v_0 at the angle θ\theta to horizon, then


(a) time taken to reach the maximum height


t=v0sin⁡θgt=\frac{v_0\sin\theta}{g}

(b) the maximum height reached


hmax=v02sin⁡2θ2gh_{\rm max}=\frac{v_0^2\sin^2\theta}{2g}

(c) the range


R=v02sin⁡2θgR=\frac{v_0^2\sin 2\theta}{g}


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