Answer to Question #96191 in Mechanics | Relativity for tusa

Question

A race car starting from rest accelerates uniformly at a rate of 4.90 meters per second2. What is the car’s speed after it has traveled 200. meters?

Answer 1

We can use the formula:

$$v_f^2-v_i^2=2as$$

$$v_f^2-0^2=2(4.9)(200)$$

$$v-f=44.3\frac{m}{s}$$