The resultant force of two forces is a vector sum of the vectors of these forces. A vector sum can be found by the law of cosines:
After setting given values we have:
Fresultant=104+104+2∗102∗102∗(−1/2)F_{resultant}=\sqrt{10^4+10^4+2*10^2*10^2*(-1/2)}Fresultant=104+104+2∗102∗102∗(−1/2)
Fresultant=104+104−104F_{resultant}=\sqrt{10^4+10^4-10^4}Fresultant=104+104−104
Fresultant=104F_{resultant}=\sqrt{10^4}Fresultant=104
Fresultant=100NF_{resultant}=100NFresultant=100N
The action angle of the resultant force equals:
γ=(α+β)/2=(170°+50°)/2=110°\gamma=(\alpha+\beta)/2=(170°+50°)/2=110°γ=(α+β)/2=(170°+50°)/2=110°
Answer: The resultant force equals 100N at 110°.
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