Angle between the two forces are:
170°−50°=120°170\degree-50\degree=120\degree170°−50°=120°
So ,
Resultant force ,
F=F12+F22+2F1F2cosθF=\sqrt{F_1^2+F_2^2+2F_1F_2\cos\theta}F=F12+F22+2F1F2cosθ
Now,
F1=F2=100 NF_1=F_2=100\ NF1=F2=100 N
And
θ=120°\theta=120\degreeθ=120°
So,
F=1002+1002+2×100×100×cos120°=100 NF=\sqrt{100^2+100^2+2×100×100×\cos120\degree}\\=100\ NF=1002+1002+2×100×100×cos120°=100 N
Direction:
Since both forces are equal so the direction of resultant force will be exactly midway between these two forces
So angle will be (170+50)2=110°\frac{(170+50)}{2}=110\degree2(170+50)=110°
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