Angle between the two forces are:
"170\\degree-50\\degree=120\\degree"
So ,
Resultant force ,
"F=\\sqrt{F_1^2+F_2^2+2F_1F_2\\cos\\theta}"
Now,
"F_1=F_2=100\\ N"
And
"\\theta=120\\degree"
So,
"F=\\sqrt{100^2+100^2+2\u00d7100\u00d7100\u00d7\\cos120\\degree}\\\\=100\\ N"
Direction:
Since both forces are equal so the direction of resultant force will be exactly midway between these two forces
So angle will be "\\frac{(170+50)}{2}=110\\degree"
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