Answer to Question #95807 in Mechanics | Relativity for kaf

Question

You are given a vector in the xy plane that has a magnitude of 81.0 units and a y component of -69.0 units.

Answer 1

The magnitude of x component is equal to

$x=\sqrt {81^2 – (-69)^2} (1)$

Using (1) we get

x=42.4, -42.4

Answer

42.4, -42.4