Answer to Question #95807 in Mechanics | Relativity for kaf

Mechanics | Relativity

Question #95807

You are given a vector in the xy plane that has a magnitude of 81.0 units and a y component of -69.0 units.

Expert's answer

The magnitude of x component is equal to

"x=\\sqrt {81^2 \u2013 (-69)^2} (1)"

Using (1) we get

x=42.4, -42.4

Answer

42.4, -42.4

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