Question

Two airplanes leave an airport at the same
time. The velocity of the first airplane is
710 m/h at a heading of 58◦
. The velocity of
the second is 630 m/h at a heading of 181◦
.
How far apart are they after 2.9 h?
Answer in units of m.

Answer 1

$$d_1=(710)(2.9)=2059\ m$$

$$d_2=(630)(2.9)=1827\ m$$

$$d=\sqrt{2059^2+1827^2-2(2059)(1827)\cos{(181-58)\degree}}$$

$$d=3417\ m$$