Answer to Question #95784 in Mechanics | Relativity for treshon

Question

A speed skater moving across frictionless ice at 8.2 m/s hits a 5.7 m -wide patch of rough ice. She slows steadily, then continues on at 5.7 m/s

Answer 1

What is her acceleration on the rough ice?

We use the formula:

$$v_f^2-v_i^2=2as$$

$$5.7^2-8.2^2=2(5.7)a$$

$$a=-3.0\frac{m}{s^2}$$