Answer to Question #95504 in Mechanics | Relativity for ethan maberry

Question

a dog is walking to the right at 1.5 (m/s) spies a cat ahead, and begins chasing the cat with a constant acceleration of 12 (m/s2). what is the velocity of the dog after runniing for 3.0 m?

Answer 1

from the formula

$v^2-v_0^2=2\cdot a \cdot s$

Where

$v_0=1.5 m/s$ -starting speed

$a=15m/s^2$ -acceleration

$s=3 m$ -the distance the dog ran

define $v$

$v=\sqrt{2\cdot a\cdot s\cdot + v_0^2}=\sqrt{2\cdot 12\cdot 3\cdot + 1.5^2}= 8.617 m/s$