Answer to Question #95309 in Mechanics | Relativity for Racquel

Question

If the 100kg crate of bananas hanging from the rope were to move downwards with a constant acceleration of 1.2 m/s^2. Find the tension in the rope

Answer 1

The Newton's second law gives

$$ma=-T+mg$$

So, the tension in the rope

$$T=m(g-a)=100\:\rm kg\times (9.8\: m/s^2-1.2\: m/s^2)=860\: N$$