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Question #95281
A car waits at a red light for a few seconds, and then accelerates straight ahead to 54 km/h in 3.1 s and then cruises at a constant speed for 75 m. The road is straight. Find the total distance and time travelled.
Expert's answer
S
=
S
a
+
S
c
s
=
S
a
+
75
S = S_{a} + S_{cs}= S_{a} +75
S
=
S
a
+
S
cs
=
S
a
+
75
S
a
=
V
0
×
t
a
+
a
×
t
a
2
2
S_{a}=V_{0}\times t_{a} +\frac{a\times t_{a}^2}{2}
S
a
=
V
0
×
t
a
+
2
a
×
t
a
2
S
a
=
V
0
×
t
a
+
(
V
−
V
0
)
×
t
a
2
S_{a}=V_{0}\times t_{a} +\frac{(V-V_{0})\times t_{a}}{2}
S
a
=
V
0
×
t
a
+
2
(
V
−
V
0
)
×
t
a
Where V
0
=0, t
a
= 3.1 s, V = 54 km/h= 15 m/s
S
a
=
15
×
3.1
2
=
23.25
m
S_{a}= \frac{15\times3.1}{2}= 23.25 m
S
a
=
2
15
×
3.1
=
23.25
m
S
=
23.25
+
75
=
98.25
m
S =23.25 +75= 98.25 m
S
=
23.25
+
75
=
98.25
m
t
=
t
a
+
t
c
s
t= t_{a}+t_{cs}
t
=
t
a
+
t
cs
t
c
s
=
S
c
s
V
=
75
15
=
5
s
t_{cs}= \frac{S_{cs}}{V}= \frac{75}{15}= 5 s
t
cs
=
V
S
cs
=
15
75
=
5
s
t
=
3.1
+
5
=
8.1
s
t= 3.1+5=8.1 s
t
=
3.1
+
5
=
8.1
s
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