Answer to Question #95201 in Mechanics | Relativity for Dalal

Question

The velocity of a particle moving along the x-axis varies according

Answer 1

The velocity of a particle moving along the x-axis varies according to the expression

$v_x(t) = (40 – 5 t^2) \frac{m}{s},$ where t is in seconds. Find the average acceleration in the time interval t=0 to t=2.0s.

$$a_x=0-2(5)t=-10t$$

The average acceleration in the time interval t=0 to t=2.0 s:

$$a_{av}=0.5(a(0)+a(2))$$

$$a_{av}=0.5(-10(0)-10(2))=-10\frac{m}{s^2}$$