Answer to Question #95186 in Mechanics | Relativity for saige

Question

a car initially traveling at 35m/s takes 2.9 sec to readh an acceleration of 8.4 m/s2. how far does the car travel?

Answer 1

The displacement of a car

$$d=v_it+\frac{at^2}{2}$$

$$=35\:\rm m/s\times 2.9\: s+\frac{8.4\:\rm m/s^2\times ( 2.9\: s)^2}{2}$$

$$=137\:\rm m$$