length of string×thicknes=area of balllength\ of\ string\times thicknes=area\ of\ balllength of string×thicknes=area of ball
l×0.2 cm=4πr2=4×3.14×102=1256l\times0.2\ cm=4\pi r^2=4\times3.14\times10^2=1256l×0.2 cm=4πr2=4×3.14×102=1256 cm
l=1256.2=6280 cm =62.8 ml=\frac{1256}{.2}=6280\ cm\\\ \ \ \ =62.8\ ml=.21256=6280 cm =62.8 m
Error in calculation will be
12×10−n=0.05\frac{1}{2}\times10^{-n}=0.0521×10−n=0.05
n=1 here because no. of digit after decimal is onen=1\ here\\\ because\ no.\ of\ digit\ after\ decimal\ is\ onen=1 here because no. of digit after decimal is one
error in calculation=0.05 m0.05 \ m0.05 m
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