Answer to Question #94991 in Mechanics | Relativity for m. Jahanzaib Hassan

Question #94991
a ball made of a long string of thickness about 2mm the radius of the ball is 10cm esimate the length of the string and possible error inyour calculation.
1
Expert's answer
2019-09-23T09:20:17-0400

length of string×thicknes=area of balllength\ of\ string\times thicknes=area\ of\ ball


l×0.2 cm=4πr2=4×3.14×102=1256l\times0.2\ cm=4\pi r^2=4\times3.14\times10^2=1256 cm


l=1256.2=6280 cm    =62.8 ml=\frac{1256}{.2}=6280\ cm\\\ \ \ \ =62.8\ m


Error in calculation will be

12×10n=0.05\frac{1}{2}\times10^{-n}=0.05


n=1 here because no. of digit after decimal is onen=1\ here\\\ because\ no.\ of\ digit\ after\ decimal\ is\ one


error in calculation=0.05 m0.05 \ m


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