Answer to Question #94975 in Mechanics | Relativity for Mehrub

Question #94975
Suppose a treadmill has an average acceleration of 0.0047 m/s^2. How much does its speed change after 4.7 seconds?
1
Expert's answer
2019-09-23T09:14:13-0400

We can use law for speed in case of uniformly accelerated motion


v=v0+atv = {v_0} + at

For the change of speed we get

Δv=vv0=at=0.0047[ms2]4.7[s]=0.02209[ms]\Delta v = v - {v_0} = at = 0.0047[\frac{m}{{{s^2}}}] \cdot 4.7[s] = 0.02209[\frac{m}{s}]


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