Answer to Question #94975 in Mechanics | Relativity for Mehrub

Question

Suppose a treadmill has an average acceleration of 0.0047 m/s^2. How much does its speed change after 4.7 seconds?

Answer 1

We can use law for speed in case of uniformly accelerated motion

$$v = {v_0} + at$$

For the change of speed we get

$$\Delta v = v - {v_0} = at = 0.0047[\frac{m}{{{s^2}}}] \cdot 4.7[s] = 0.02209[\frac{m}{s}]$$