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Question #94520
The velocity of a particle is given by v =
v0
1 + At2
, where v0 = 25 m s−1
and A = 2.0 s−2
. What
is the acceleration at t = 0? At t = 2.0 s? At t → ∞?
Expert's answer
The velocity of a particle
v
(
t
)
=
v
0
(
1
+
A
t
2
)
=
25
(
1
+
2.0
t
2
)
v(t)=v_0(1+At^2)=25(1+2.0t^2)
v
(
t
)
=
v
0
(
1
+
A
t
2
)
=
25
(
1
+
2.0
t
2
)
The acceleration of a particle
a
(
t
)
=
d
v
(
t
)
d
t
=
(
25
(
1
+
2.0
t
2
)
)
′
=
100
t
a(t)=\frac{dv(t)}{dt}=(25(1+2.0t^2))'=100t
a
(
t
)
=
d
t
d
v
(
t
)
=
(
25
(
1
+
2.0
t
2
)
)
′
=
100
t
So
a
(
0
)
=
0
m
/
s
2
a(0)=0\:\rm m/s^2
a
(
0
)
=
0
m/
s
2
a
(
2.0
)
=
200
m
/
s
2
a(2.0)=200 \:\rm m/s^2
a
(
2.0
)
=
200
m/
s
2
a
(
∞
)
=
∞
a(\infty)=\infty
a
(
∞
)
=
∞
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