Answer to Question #94519 in Mechanics | Relativity for Evalex

Question #94519
What kind of energy does an orange fruit still on the branch of the tree that 3m tall. Take the acceleration due to gravity as 9.8m/s2 and the mass of the orange is assumed to be 2g
1
Expert's answer
2019-09-16T09:51:22-0400

We are talking about the potential energy in the gravity field of the Earth.

As long as the orange is stationary, the kinetic energy is 0.


Potential energy:

U=mgh=2103 kg 9.8ms23 m=0.0588 J=5.88102 J=58.8 mJ.U = mgh = 2\cdot10^{-3}\text{ kg }\cdot 9.8\frac{\text{m}}{\text{s}^2}\cdot3\text{ m} = 0.0588\text{ J} = 5.88\cdot10^{-2}\text{ J} = 58.8\text{ mJ}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment