The displacement of the car is described by equation
"d=v_it+\\frac{at^2}{2}=\\frac{at^2}{2}"The acceleration of the car
"a=\\frac{\\Delta v}{\\Delta t}=\\frac{25\\:\\rm m\/s-0\\: m\/s}{10\\:\\rm s}=2.5\\:\\rm m\/s^2"So
"d=\\frac{2.5t^2}{2}=1.25t^2"
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