Question

what is the efficiency of pump if 1500 watt and work output 12000 J in 10 seconds

Answer 1

$$\rm efficiency=\frac{output\: work}{input\: work}$$

$$\eta=\frac{W_{output}}{W_{input}}=\frac{12000\:\rm J}{1500\:\rm W\times 10\:\rm s}=0.8=80\%$$