Answer to Question #93544 in Mechanics | Relativity for Jarod P Barba

Question

A dog jogs 4m down a hall in 2 seconds and jogs 3m down a perpendicular hall in 1.5 seconds. What was its average speed? What was its average velocity?

Answer 1

(a)

$${\rm Average\; speed}=\frac{{\rm Total\; distance}}{{\rm Total\; time}}$$

$$=\frac{4\:\rm{m}+3\:\rm{m}}{2\:\rm{s}+1.5\:\rm{s}}=2\:\rm{m/s}$$

(b)

$${\rm Average\; velocity}=\frac{{\rm Total\; displacement}}{{\rm Total\; time}}$$

$$=\frac{\sqrt{(4\:\rm{m})^2+(3\:\rm{m})^2}}{2\:\rm{s}+1.5\:\rm{s}}=1.4\:\rm{m/s}$$