Question #93099
5.) A car traveling at 15 m/s passes a van that is starting from rest with an acceleration of 3 m/s². (a) How long will it take the van to catch up with the car? (b) How far has the car traveled when the van catches up with it?
1
Expert's answer
2019-08-27T09:33:46-0400

Let after time t sect \space sec ,van catches up the car.

(a) So,distance traveled by car in tt seconds:

ucart=uvant+12at2;uvan=0u_{car}t=u_{van}t+\frac{1}{2} at^2 ;u_{van}=0

15t=12×a×t215 t=\frac{1}{2}\times a \times t^2

a=3m/sec2a=3 m/sec ^2

Solving this equation :

15t=12×3t215 t=\frac{1}{2}\times 3 t^2

t=10 sect=10 \space sec

(b) Distance traveled by car in 10 sec=10 \space sec =  ucart=15×10=150m\space u_{car}t=15 \times 10=150 m


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