Let after time "t \\space sec" ,van catches up the car.
(a) So,distance traveled by car in "t" seconds:
"u_{car}t=u_{van}t+\\frac{1}{2} at^2 ;u_{van}=0"
"15 t=\\frac{1}{2}\\times a \\times t^2"
"a=3 m\/sec ^2"
Solving this equation :
"15 t=\\frac{1}{2}\\times 3 t^2"
"t=10 \\space sec"
(b) Distance traveled by car in "10 \\space sec =" "\\space u_{car}t=15 \\times 10=150 m"
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