Distance traveled by car before any reaction=
"u \\times t=15 \\times 2=30 m"
Distance remaining between car and truck=5 m
Car stops 4 m away from truck,so distance traveled by car is 1 m and velocity of car comes down to zero.
By equation of motion,
"v^2-u^2=2as.......(v=0)"
"a=-\\frac{u^2}{2s}=-\\frac{15^2}{2 \\times 1}=-112.5 m\/sec^2"
("- ve" sign shows retardation)
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