Displacement of the particle = diameter of the semicircle "d = 2*6 = 12 m."
Particle motion time "t=L\/v," where "L" is length of the semicircle, "v" is speed of the particle along the semicircle.
Average velocity "v_{av}=d\/t=d\/L\\cdot v=2\\cdot 6 \/(\\pi\\cdot 6)\\cdot 12 = 24\/\\pi" m/s
Answer: "24\/\\pi" m/s.
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