Question

4.) A car is accelerated from 2.0 m/s to 5.0 m/s in 1.5 s. Find (a) the magnitude of its acceleration and (b) the distance traveled during the time of observation?

Answer 1

(a) The magnitude of its acceleration is equal to

$\frac {5-2}{1.5}=2$

Answer

2 m/s²

(b) We can write

$2as=v_{2}^2 - v_{1}^2 (1)$

In our case, we have

V₂= 5.0 m/s

V₁= 2.0 m/s

a=2 m/s²

Using (1) we get

s=5.25 m

Answer

5.25 m