Answer to Question #92542 in Mechanics | Relativity for m

Question #92542
The acceleration of a point is given by a=5-t^2. write an equation for velocity if v=4 m/s when t=3 s
1
Expert's answer
2019-08-12T10:07:34-0400

Velocity of the point

v(t)=a(t)dt=(5t2)dt=5tt33+v0v(t)=\int a(t)dt=\int (5-t^2)dt=5t-\frac{t^3}{3}+v_0

v(3)=5×3333+v0=4v(3)=5\times 3-\frac{3^3}{3}+v_0=4

v0=2m/sv_0=-2 \:\rm{m/s}

Finally, the equation for velocity

v(t)=5tt332v(t)=5t-\frac{t^3}{3}-2


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