Question #92487
A retarding force f=-2v is acting on a body of mass 10 gram. Find out time taken for its velocity to reduce to 37% of its initial value if initial velocity is 1m/s
1
Expert's answer
2019-08-12T09:56:35-0400

According to the Newton's second law and according to the task

mdv(t)dt=2v(t)m\frac{dv(t)}{dt}=-2v(t)

Solution of the equation with the initial condition

v(0)=v0v(0)=v_0

is

v(t)=v0exp(2tm)v(t)=v_0\exp \left(-\frac{2t}{m}\right)

So the time taken for its velocity to reduce to 37% of initial value can be found from the equation

v(t)=0.37v0v(t)=0.37v_0

The solution is

t=m2ln(0.37)t=-\frac{m}{2}\ln(0.37)

And according to the task

t5mst\approx5\:\mathrm{ms}

We can see that the result doesn't depend on initial velocity.


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