Answer to Question #92353 in Mechanics | Relativity for Fatima

Question

3) What work is done by a force F=(2i+4j)N, that moves a particle from a position ri=(3i+4j)m to a position rf=(-4i-2j)m?

Answer 1

The work is given by formula

$$W=\vec{F}×\vec{s} (1)$$

In our case, we have

$$\vec{s} =(-4i-2j) - (3i+4j)=-7i-6j (2)$$

We put (2) in (1)

$$W=(2i+4j)( -7i-6j) = -14i - 24j=-38$$

Answer

-38 J