Answer to Question #92226 in Mechanics | Relativity for Isaac

Question #92226
Calculate the force exerted on a car of mass 1 ton, that moved with velocity of 45km/hr on a rough road and it is brought to rest after 10 seconds
1
Expert's answer
2019-08-02T10:26:32-0400

The Newton's second law states

F=maF=ma

The acceleration of a car

a=ΔvΔt=0m/s45(1000m/3600s)10s=1.25m/s2a=\frac{\Delta v}{\Delta t}=\frac{0\:\rm{m/s}-45(\rm{1000\:m/3600\: s})}{10\:\rm{s}}=-1.25\:\rm{m/s^2}

Finally, the magnitude of the force exerted on a car

F=1000kg×1.25m/s2=1250NF=1000\:\rm{kg}\times 1.25\:\rm{m/s^2}=1250\:\rm{N}


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