According to Newton’s second law:
"F = ma"
"OX: ma = F_{friction}"
"ma = \\mu mg"
"a = \\mu g"
"\\mu = a\/g"
Wherein:
"S = {v^2 -v_0^2 \\over 2a} = {v_0^2 \\over 2a}"From here:
"a = {v_0^2 \\over 2S} = {250 \\over 380} = 0.66 m\/s^2"As a result:
"\\mu = 0.66\/10 = 0.066"Answer: 0.066
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