Answer to Question #92102 in Mechanics | Relativity for Favour Ongbabo

Question

A 50kg box is pushed across a horizontal floor by a horizontal force of 150N through a distance of 12m. Given that the kinetic friction is 0.3.
i)How much work went into overcoming friction?
ii)How much work went into accelerating the box?

Answer 1

i)

The work went into overcoming friction is given by formula

$W=µmgs (1)$

In our case, µ=0.3, m=50 kg, s=12 m

Using (1) we got

W=1764 J

Answer:

1764 J

ii)

The work went into accelerating the box is given by formula

$W=Fs (2)$

In our case, F=150 N, s=12 m

Using (2) we got

W=1800 J

Answer:

1800 J