Question

An 8.5x10^2 kg elevator is pulled up 32.0m at a constant velocity of 1.4m/s. Calculate the power output of the motor.

Answer 1

$${\rm{Power}}=\frac{\rm{Work\;done}}{\rm{Time}}=\frac{mgh}{t}=mgv$$

$$=8.5\times 10^2\:\rm{kg}\times 9.8\:\rm{N/kg}\times 1.4\:\rm{m/s}=11662\:\rm{W}$$