Question

a force applied on a body of1.2kg for 0.2 s and the body travelled a distance of 2m in the next round. Find the force applied on th body.

Answer 1

The Newton's second law states

$$F=ma$$

The distance travelled by body

$$d=\frac{at^2}{2}$$

So

$$F=m\times \frac{2d}{t^2}$$

$$=1.2\:\rm{kg}\times \frac{2\times 2\:\rm{m}}{(0.2\:\rm{s})^2}=120\:\rm{N}$$