Answer to Question #91601 in Mechanics | Relativity for Arena

Question

What is the acceleration of a meteor at a distance 8*10^6m from the center of the earth?

Answer 1

Using Newton's law of gravitation

$F_{gravitational}=G*M_{earth}*m_{meteor}/r^2$

Using Newton's law

$F=m*a$

$a_{meteor}=(G*M_{earth}*m_{meteor}/r^2)/m_{meteor}=$

$a_{meteor}=(G*M_{earth}/r^2)=$

$6.674*10^{-11}*5.972*10^{24}/(8*10^6)^2=6.22768 m/s^2$

Answer: 6.22768 m/s².