Question #91280
a block A weight of 320N resting on a rough horrizontal floor supports a block B 160 N. The two blcok connecting to a string passing arround a smooth pulley. Determine the horizontal force P that has to be applied on block A so as to just move it towards right.take miu=0.25 at all contact surface and also determine the tension T in the string respectively.
1
Expert's answer
2019-07-01T09:29:19-0400

According to Newton's second law, we can writer for a block A


P=Ffriction+T(1)P=F_{friction} + T (1)

wher P is the horizontal force, T is the tension in the string


Friction force is given by formula


Ffriction=kMg(2)F_{friction}=kMg (2)

The tension in the string is equal to


T=mg(3)T=mg (3)

We put (2) and (3) in (1):

P=kMg+mg(4)P=kMg + mg (4)

In our case we have


M=32 kg, m=16 kg, k=0.25


Using (4) we get:


P=240 N


Using (3) we get:


T=160 N


Answer:

P=240 N

T=160 N


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