Question #91277
A car accelerates from rest at a constant rate α for some time after which it decelerates at a constant rateβ and comes to rest. if total time elasped is t, then maximum velocity acquired by car will be
1
Expert's answer
2019-07-01T09:28:42-0400

The maximum velocity acquired by car:


v=αt1=βt2v=\alpha t_1=\beta t_2

t=t1+t2t=t_1+ t_2

Thus,


t=vα+vβt=\frac{v}{\alpha}+\frac{v}{\beta}

v=t1α+1βv=\frac{t}{\frac{1}{\alpha}+\frac{1}{\beta}}


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