Answer to Question #91261 in Mechanics | Relativity for Umar

Question #91261
An engine raises 100kg of water through a height of 60m in 20s. What is the power of the engine?
(g= 10m/s)
1
Expert's answer
2019-07-04T09:24:20-0400

We can find the power of the engine from the formula:


P=Wt=mght=100kg10ms260m20s=3.0103W=3.0kW.P = \dfrac{W}{t} = \dfrac{mgh}{t} = \dfrac{100kg \cdot 10 \dfrac{m}{s^2} \cdot 60 m}{20s} = 3.0 \cdot 10^3 W = 3.0 kW.

Answer:

P=3.0103W=3.0kW.P = 3.0 \cdot 10^3 W = 3.0 kW.


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