Question #91239
A soccer player starts from rest and accelerates forward, reaching a velocity of 8.00m/s in 2.50s. a) What was his average acceleration? b) what average force did he exert backward on the ground to achieve this acceleration? The players mass is 70.0kg, and air resistance is negligible
1
Expert's answer
2019-07-01T09:26:52-0400

a)


aavg=ΔvΔt=82.5=3.20ms2a_{avg}=\frac{\Delta v}{\Delta t}=\frac{8}{2.5}=3.20\frac{m}{s^2}

b)


F=maavg=(70)(3.2)=224 NF=ma_{avg}=(70)(3.2)=224\ N


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