Answer to Question #91228 in Mechanics | Relativity for Isaac Boshe

Question

The displacement of a particle S is given by S=A+Bt+Ct^2. Deduce the units of the constants A, B and C.

Answer 1

$$[S]=[A+Bt+Ct^2]$$

Thus,

$$[A]=[S]=m$$

$$[B]=\frac{[S]}{[t]}=\frac{m}{s}$$

$$[C]=\frac{[S]}{[t]^2}=\frac{m}{s^2}$$