Question #91223
the time for 10 vibration of simple pendulum recorded by stop watch is 17.5 s +- 0.1 s .The uncertainity in final result is
(a) o.1s
(b)o.oo6s
(c) 0.01s
(d)0.02s
1
Expert's answer
2019-07-01T09:11:19-0400

The period is


T=17.510=1.75 sT=\frac{17.5}{10}=1.75\ s

The in final result is  


ΔT=0.110=0.01 s\Delta T=\frac{0.1}{10}=0.01\ s

Answer: c) 0.01s 


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Comments

Assignment Expert
01.07.19, 16:12

Dear visitor, please use panel for submitting new questions

wahab ullah
28.06.19, 19:14

The percentage uncertaunity in mass and spring constant in time period of spring mass system respectively are 2 % and 6 %. the percent uncertainity in time period will be (a) 3 % (b) 4% (c) 8% (d) none

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