Answer to Question #91223 in Mechanics | Relativity for wahab ullah

Question

the time for 10 vibration of simple pendulum recorded by stop watch is 17.5 s +- 0.1 s .The uncertainity in final result is
(a) o.1s
(b)o.oo6s
(c) 0.01s
(d)0.02s

Answer 1

The period is

$$T=\frac{17.5}{10}=1.75\ s$$

The in final result is  

$$\Delta T=\frac{0.1}{10}=0.01\ s$$

Answer: c) 0.01s