Question #90999
a fisherman sailed farther to sea to find a good catch. He sailed directly east for 55.3 km. Then he sailed Northeast for 25.0 km. From that point. He continued sailing toward a straight path and found himself 200 km. East from his original posisition.
1
Expert's answer
2019-06-25T09:13:34-0400

If you draw an image of the fisherman's adventure, the problem becomes way more easier:



So, we can write an equation using the horizontal and vertical projections of his path:


200=55.3+25 sin 45+x sin α,200=55.3+25\space\text{sin}\space 45^\circ+x\space\text{sin}\space\alpha,

in vertical direction the fisherman's displacement is 0:

0=25 cos 45+x cosα.0=25\space\text{cos}\space45^\circ+x\space\text{cos}\alpha.

Solve this system and get that


x=128.25 km,α=97.92.x=128.25\text{ km}, \alpha=97.92^\circ.


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