Question

A rocket with a mass of 400 lbm travels at 27000 ft/sec. What is it's kinetic energy in ft-lbf

Answer 1

The kinetic energy:

$$K=0.5mv^2$$

$$m=400\ lb_m=\frac{400}{32.174}slugs$$

$$K=0.5\frac{400}{32.174}(27000)^2=4.5\cdot 10^9\ ft \cdot lb_f$$