Question #90831
A 1.0- kg wheel with moment of inertia about its axis I = MR^2 is rolling without slipping on the horizontal ground. Its center of mass has an acceleration of 5.0 m/s^2. The frictional force exerted on the wheel from the ground is ?
1
Expert's answer
2019-06-17T12:58:57-0400

As the only force actiong on the wheel is friction, according to the second Newton's law:


Ffric=maF_{fric}=ma

where aa - acceleration of the center of mass.

Then,


Ffric=ma=15=10NF_{fric}=ma=1*5=10 N


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