Question #90610
A free-fall ride takes 2.35 s. to fall from it’s maximum height. How tall is the ride?
1
Expert's answer
2019-06-06T10:00:39-0400

For free fall we write [1]


y=y0+v0tgt22y=y_0+v_0t-\frac{gt^2}{2}

We have t=2.35s,y(2.35)=0,v0=0,g=9.8m/s2.t=2.35\,s, \, y(2.35)=0,\, v_0=0, g=9.8\, m/s^2. So,

y0=gt22=9.82.352227.06m.y_0=\frac{gt^2}{2}=\frac{9.8 \cdot 2.35^2}{2}\approx 27.06\, m.

[1] https://en.wikipedia.org/wiki/Free_fall#Free_fall_in_Newtonian_mechanics


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