Answer to Question #90442 in Mechanics | Relativity for AWESOME

Question

a GAS EXPANDS BY 1.2 LITRES AT A CONSTANT PRESSURE OF 2.5 BAR. DURING THE EXPANSION, 500j OF HEAT IS ADDED. FIND THE CHANGE IN THE INTERNAL ENERGY OF THE GAS

Answer 1

according to the first law of thermodynamics

$$\Delta U = Q - p \Delta V = 500 - 1.2\cdot2.5\cdot10^{2} = 200 (J)$$