Question #90433
What is the magnitude of force on a particle of mass 20kg with a displacement function of S = 12.5t + t2
1
Expert's answer
2019-06-03T10:18:54-0400
s(t)=12.5t+t2a(t)=s¨(t)=2F=ma=40Ns(t)=12.5 t +t^2\\ a(t) = \ddot{s}(t) = 2\\ F=ma=40\,N

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