Question #90399
Niagara falls are 50m high. calculate the potential energy of 0.1 cubic meter of water at the top relative to the bottom. density of water is 1000 kg m^-3. take g= 10m/s^2
1
Expert's answer
2019-05-31T09:44:06-0400

Potential energy is:

E=mghE=mgh

Mass:

m=ρVm=\rho*V

then:

E=ρVgh=1000×0.1×10×50=50000J=50kJE=\rho Vgh=1000\times 0.1\times 10 \times 50 = 50000 J = 50 kJ


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