Question #90397
A stone of mass 50kg released from a heigth of 2m above the ground level if the stone falls freely to a heigth of 5m above the ground, its velocity is?
1
Expert's answer
2019-06-03T09:55:20-0400

From the conservation of enegy:


mgH=mgh+0.5mv2mgH=mgh+0.5mv^2

The velocity:


v=2g(Hh)v=\sqrt{2g(H-h)}

v=2(9.8)(205)=17msv=\sqrt{2(9.8)(20-5)}=17\frac{m}{s}


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Comments

Favour Adetomiwa
23.01.22, 21:59

Greatness ❤️❤️❤️❤️.. Correct expert

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