The body acceleration
"a=\\frac{F}{m}=\\frac{72\\:\\rm{N}}{108\\:\\rm{kg}}=0.67\\:\\rm{m\/s^2}"The distance
"d=\\frac{at^2}{2}"So, time taken to cover the distance
"t=\\sqrt{\\frac{2d}{a}}=\\sqrt{\\frac{2\\times 300\\:\\rm{m}}{0.67\\:\\rm{m\/s^2}}}=30\\:\\rm{s}"
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