Question #90103
Calculate the maximum monochromatic emissive power at 288k
1
Expert's answer
2019-05-27T11:29:29-0400

Wien’s Displacement Law:

Eλ=C1λ5expC2λT1E_{\lambda}=\frac{C_1\lambda^{-5}}{exp^{\frac{C_2}{\lambda T}}-1}

the wavelength at which emissive power is maximum:


λmax=C24.965×T=0.0029Tm\lambda_{max}=\frac{C_2}{4.965\times T}=\frac{0.0029}{T} m

If we substitute this wavelength in the Wien's Displacement law, then the magnitude of the maximum monochromatic emissive power is


Emax=1.285×105×T5=1.285×105×2885=25.46×106Wm2E_{max}=1.285\times 10^{-5}\times T^5=\\ 1.285\times 10^{-5}\times 288^5 = 25.46\times 10^6 \frac{W}{m^2}



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